Answer: D
Let the number be xy.
The number = 10x+y
On interchanging the digits of the number = 10y+x
=> 10x+y - 10y-x = 27
=> x-y = 3
Now, y is not equal to zero and the set of digits satisfying the condition are :-
(9,6), (8,5), (7,4), (6,3), (5,2), (4,1)
We can't reach on the distinct answer.